X^2-26x+88=0

Solution for X^2-26x+88=0 equation:

X^2-26X+88=0

a = 1; b = -26; c = +88;
Δ = b2-4ac
Δ = -262-4·1·88
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-18}{2*1}=\frac{8}{2}
=4
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+18}{2*1}=\frac{44}{2}
=22
$